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Sunday, February 28, 2021
Saturday, February 27, 2021
Friday, February 26, 2021
CBSE Chemistry Practical sample paper-2020-21
Jawahar Navodaya Vidyalaya, West Singhbhum
Class - XII Subject -chemistry practical(043)
full Marks-30 Time - 3 Hours
Set-I
1. Prepare M/20 solution of Oxalic acid. using this solution find out the molarity & strength of the given KMnO4 solution. (8)
2. Determine the cation & anion in the given unknown salt sample [ A ] (8)
3. Determine the functional group in the given unknown organic compound (P) [6]
4. Class record & viva [4]
5 . Investigatory project [4]
Set-II
1. Prepare M/50 solution of ferrous ammonium sulphate (Mohr's salt) . using this solution find out the molarity & strength of the given KMnO4 solution. (8)
2. Determine the cation & anion in the given unknown salt sample [ B ] (8)
3. Determine the functional group in the given unknown organic compound (Q) [6]
4. Class record & viva [4]
5 . Investigatory project [4]
Wednesday, February 24, 2021
Tuesday, February 23, 2021
E-magazine
Here, there are many links of various type of magazine in the given below page. so you click on magazine whatever you want to read.
Monday, February 22, 2021
Sunday, February 21, 2021
Thursday, February 18, 2021
Solid states- very short and short answer type question
Topic: Solids and their classification
1. What are fluids? Give examples. [1]
2. Solids are rigid why? [1]
3. How are solids classified? [1]
4. Define the term amorphous with example. [1]
5. The window panes of the old buildings are thick at the bottom. Why? [2]
6. The stability of a crystal is reflected in the magnitude of its melting point. Explain [2]
7. Graphite is soft and good conductor of electricity. Explain. [2]
8. Ionic solids are good conductors in molten state and in aqueous solutions but not in solid state. Why [2]
9. Differentiate between amorphous and crystalline solids with reference to (1) Melting point (2) Cleavage property (3) Nature [3]
10. How are crystalline solids classified on the basis of nature of bonding? Explain with examples. [3]
ANSWERS
Topic: Solids and their classification.
Ans 1: Substances which flow are fluids e.g. liquids and gases.
Ans 2: Rigidity in solids is due to fixed positions of the constituent particles and their oscillations about their mean positions
Ans 3: Solids may be classified into two categories – crystalline and amorphous.
Ans 4: Amorphous means disordered and random arrangement of particles for example – silica, plastic, rubber
Ans 5: Glass panes of old buildings are thicker at the bottom than at the top as from is an amorphous solid and flows down very slowly and makes the bottom portion thicker.
Ans 6: Melting point of a solid gives an idea about the intermolecular forces acting between particles. When these forces are strong, the melting point is higher and when these forces are weak, low melting point is observed. Higher is the melting point, more stable the solid is.
Ans 7: Graphite is soft and good conductor due to its typical structure here carbon atoms are arranged in different layers and each atom a covalently bonded to three of its neighbouring atoms in the same layer. The fourth electron of each atom is free to move about due to which it conducts electricity. Different layers can slide over the other which makes it a soft solid.
Ans 8: In the solid state, the ions in the ionic solids are not free to move about due to their rigid structure & strong electrostatic forces. Therefore they cannot conduct electricity whereas in molten state and aqueous solution, the ions become free to move about and they conduct electricity.
Ans 9:
Property |
Crystalline
solids |
Amorphous
solids |
1. Melting point |
They have sharp melting point |
They have a range of melting point. |
2. Cleavage property |
They split into pieces of plain and smooth surfaces
when cut with a sharp edged tool. |
When cut with a sharp edged tool, pieces of
irregular surfaces are obtained. |
3. Nature |
They are true solids. |
They are pseudo solids or super cooled liquids. |
Ans 10: Classification of crystalline solids.
1. Molecular solids: The forces operating between molecules are dispersion or London forces, dipole-dipole interactions, hydrogen bounding e.g. CCl4, HCl, ice etc.
2. Ionic solids: The intermolecular forces are coulomibic or electrostatic forces, e.g. NaCl, MgO etc.
3. Metallic solids: The forces operating is metallic bonding e.g. Fe, Cu, Ag etc.
4. Covalent or network solids: The attractive forces are covalent bonding e.g Diamond, Quartz etc.
Topic: Structures of crystals
1. Define the term: Crystal lattice [1]
2. What is a unit cell? [1]
3. What are the axial angles and edge length in a cubic crystal system? [1]
4. Give one example of each – Tetragonal and hexagonal crystal system. [1]
5. Name three types of cubic unit cells? [1]
6. How many atoms are there in a unit cell of a metal crystallizing in a: [2]
(a) FCC structure
(b) BCC structure
7. What is the contribution of an atom per unit cell if the atom is: [3]
(a) At the corner of the cube. (b) On the face of the cube. (c) In the centre of the cube.
8. A compound formed by A & B crystallizes in the cubic structure where ‘A’ are at the corners of the cube and B are at the face centre. What is the formula of the compound? [2]
9. Calculate the no. of atoms in a cubic based unit – cell having one atom on each corner and two atoms on each body diagonal. [2]
10. What is the no. of octahedral and tetrahedral voids present in a lattice? [2]
ANSWERS
Topic: Structures of crystals
Ans 01: The three dimensional diagrammatic representation of constituent particles, in which each particle is depicted as a point is called crystal lattice.
Ans 02: The smallest portion of a crystal lattice which, when, repeated in different directions, generates the entire lattice, is called its unit cell.
Ans 03: Axial angles, 0 α β γ = 90 and edge lengths a = b = c.
Ans 04: Tetragonal crystal system – white tin, SnO2. Hexagonal crystal system – Graphite, ZnO.
Ans 05: (a) Simple cubic (b) Face – centred cubic (c) Body centred cubic
Ans 06: (a) FCC = 4 (b) BCC = 2
Ans 07: (a) When atom is at the corner of the cube, the contribution is 1/8 atom.
(b) When the atom is on the face of the cube, its contribution is ½ atom.
(c) If the atom is in the centre of the cube, its contribution is 1 atom.
Ans 08: Contribution of atom A per unit cell = 1/8 ×8 = 1 atom
Contribution of atom B per unit cell =½ ×6 = 3atom
Ratio of A & B = 1:3 Formula = AB3
Ans 09: No. of atoms contributed by 8 corners per unit cell = 1/8 x 8 = 1 atom.
No. of atoms contributed by one diagonal = 2
No. of diagonal = 4
∴Total contribution by diagonal = 4× 2 = 8
∴Total no. of atoms = 8 + 1 = 9 atoms
Ans 10: No. of octahedral voids present in a lattice is equal to the no. of close packed particles and the number of tetrahedral voids is twice the no. of close packed particles.
Topic – Packing in crystals
1. What is square close packing? [1]
2. What is the coordination number in :-
(a) Square close packing
(b) Hexagonal close packing. [1]
3. Define – (a) void (b) coordination Number [2]
4. What is the packing efficiency in
(a) hcp structure (b) BCC structure (c) Simple cubic structure [3]
5. Give the relationship between density and edge length of a cubic crystal. [2]
6. Copper which crystallizes as a face – centred cubic lattice has a density of 8.93 g/cm3 at 20o C. calculate the length of the unit cell. [3]
7. An element crystallizes in BCC structure. The edge of its unit cell is 288 pm. If the density is 7.2 g/cm3 . calculate the atomic mass of the element. [3]
8. The compound CuCl has ZnS structure and the edge length of the unit cell in 500 pm. Calculate the density. (Atomic masses: Cu = 63, Cl = 35.5, Avogadro no = 6.02´ 1023 mol-1) [3]
9. In a compound, B ions form a close – packed structure & A ions occupy all the tetrahedral voids. What is the formula of the compound? [2]
10. In crystalline solid, anions C are arranged in cubic close – packing, cations A occupy 50% of tetrahedral voids & cations B occupy 50% of octahedral voids. What is the formula of solid? [3]
[ANSWERS] Topic – Packing in crystals
Ans 01: The close packing of spheres – atoms or ions, in which each sphere is in contact with four of is neighbours, whose centres, if joined, form a square, is called square close packing.
Ans 02: (a) in square close packing, the coordination no. is 4. (b) In hexagonal close packing, the coordination no. is 12
Ans 03 (a) void – the empty space left between close packed spheres are voids. (b) Coordination number – the number of spheres or atoms surrounding a single sphere or atom in a crystal is called coordination number.
Ans 04: (a) hcp packing efficiency is 74%. (b) bcc packing efficiency is 68%. (c) packing efficiency in simple cubic structure is 52.4%.
Ans 05: Density, d of a cubic cell is given by
d = ZM/a3Na
Where Z = no. of atoms per unit cell M = molar mass NA = Avogadro number a = edge length
Ans 06: 361.6 pm (hint 4r = √2 a)
Ans 07: 52 g/ mol ( Hint- Z= 2 ,d = ZM/a3Na)
Ans 08: 5.22 g/cm3 (Hint d = ZM/a3Na )
Ans 09: Let the no. of B ions = 100
No. of A ions = no. of tetrahedral voids
= 2 ´no. of ions in close – packed structure = 2 ´ 100 = 200
Ratio of A & B = 200 : 100 = 2 : 1 Formula = A2B.
Ans 10: Suppose no. of anions, C = 100
Suppose no. of cations, A = 50/100 ´ no. of tetrahedral voids
= ½ (2 ´ C)
No. of cations, B = 50/100 ´ no. of octahedral voids
= ½ ´ C
= ½ ´ 100 = 50
Ratio of ions A : B : C = 100 : 50 : 100
= 2 : 1 : 2
Formula = A2BC2
Topic – imperfections in crystals
1. What is the meaning of term ‘defect’
with reference to crystal? [1]
2. Define two main types of defects. [2]
3. Name the types of point defect. [1]
4. (a) Identify the defect in figure below : [2]
(b) How does it affect the density of crystal?
(c) Give an example of crystal where this defect can be found.
(d) What is its effect on electrical neutrality of crystal?
5. Which defect is observed in a solid solution of CdCl2 and AgCl? Explain. [2]
6. Excess of lithium makes LiCl crystal
pink. Explain. [2]
7. What are F centres? [1]
8. How does a crystal changes due to
presence of F centre? [1]
9. Give an example which shows both frenkel
and Schottky defect. [1]
10. Which type of ionic substances show? [2] (a) Schottky defect (b) Frenkel defect
[ANSWERS] Topic – imperfections in crystals
Ans 01: The defects are irregularities in
the arrangement of constituent particles in a crystal.
Ans 02: Defects are of two types – Point
defects: - Irregularities or deviations from ideal arrangement around a point
or on atom in a crystal. Line defect: - Irregularities or deviation from ideal
arrangement in entire row of lattice points.
Ans 03: point defects are of three types –
stoichiometric defect, impurity defect & non – stoichiometric defect.
Ans 04: (a) Schottky defect. (b) It
decreases the density of crystal. (c) NaCl, KCl (d) The crystal remains
electrically neutral.
Ans 05: In a solid solution of CdCl2 and AgCl, impurity defect is observed. In the crystal of AgCl, some of the sites of Ag+ are occupied by Cd2+ , each Cd2+ replacing two Ag+. It replaces the site of one ion and other site remains vacant.
Ans 06: When crystals of LiCl are heated in
an atmosphere of Li vapour the Lithium atoms are deposited on the surface of
crystal. The Cl- ions diffuse to the surface of crystal & combine with Li
atoms to from LiCl which happens by loss of electrons by Li atoms to form Li+
ions. These released elements diffuse into the crystal & electrons get
excited after absorbing light from visible region & emit pink colour.
Ans 07: F – centre is the position of an
anion in an ionic crystal which is occupied by a trapped electron
Ans 08: The crystal becomes paramagnetic
and coloured due to presence of f – centre
Ans 09: AgBr.
Ans 10: (a) Schottky defect – ionic
substances in which the cation and anion are of almost similar sizes eg. NaCl,
KCl, CrCl.
(b) Feenkel Defect – Ionic substances in
which there is large difference in size of ions eg. ZnS, AgCl, AgBr.
Chemical reactions and equations -important questions with answer
MULTIPLE CHOICE QUESTIONS
1. Barium chloride on reacting with ammonium sulphate forms barium sulphate and ammonium chloride. Which of the following correctly represents the type of the reaction involved?
(a) Displacement reaction
(b) Decomposition reaction
(c ) Combination reaction
(d) Double displacement reaction
2. Chemically rust is
(a) ferric sulphate
(b) ferric oxide
(c)hydrated ferrous oxide
(d) hydrated ferric oxide
3. When green colour ferrous sulphate crystals are heated, its colour changes as
(a) it is decomposed to ferric oxide
(b) it loses water of crystallisation
(c) it forms SO2
(d) it forms SO3
FILL IN THE BLANKS
4. Precipitation reactions are type of
5. Decomposition of calcium carbonate forms and .
6. Magnesium ribbon is rubbed with sand paper to remove .
ONE MARK QUESTIONS
7. Name the gas produced by the action of dilute hydrochloric acid on zinc granule.
8. Which gas is used to prevent rancidity in potato chips packets?
9. Write one equation to represent thermal decomposition.
ASSERTIONS AND REASON
For the question numbers 10, 11 and 12, two statements are given- one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer to these questions from the codes (a), (b), (c) and (d) as given below:
(a) Both A and R are true and R is the correct explanation of A.
(b) Both A and R are true but R is not the correct explanation of A.
(c) A is true but R is false.
(d) A is false but R is true.
1. Assertion: Colour of copper sulphate solution does not change when the iron nail is kept in it. Reason: Iron is more reactive than copper and displaces it.
2. Assertion: Combustion reaction is also called an exothermic oxidation reaction. Reason: In this reaction oxygen is added and heat energy is released.
3. Assertion: Pungent smelling gas is produced when sulphur burns in air. Reason: Sulphur dioxide is formed on the reaction of sulphur with oxygen.
FIVE
MARK QUESTIONS
1.
(a) Barium chloride
reacts with aluminium
sulphate to give aluminium chloride
and barium sulphate.
(i) State the type of reaction.
(ii) Translate the
above statement into a balanced chemical equation.
(b) A metal ‘X’
acquires a green colour coating on its surface on exposure to air.
(i) Identify the
metal ‘X’ and name the process responsible for this change.
(ii)
Name and write the chemical formula of the green colour coating
formed on the surface of the metal.
2.
2g of Ferrous Sulphate crystals
are heated in a boiling
tube.
(i) State the colour of Ferrous Sulphate crystals both before heating and after heating.
(ii) Name the gases produced during heating.
(iii) Write the chemical equation for the reaction.
(b) Describe an activity to show a decomposition reaction in which
light is used to decompose a reactant. Write the chemical equation of the
reaction and state one of its uses.
3.
(a)Why is it essential to balance a chemical equation?
(b) With the help of a chemical reaction, explain the decomposition of lead nitrate.
(c)Can rusting of iron take place in distilled water? Give a
reason.
(d) Give two methods
to prevent rancidity.
(e)
How will you test for the gas which is liberated when HCl reacts with an active metal?
4.
CASE- STUDY
Answer question
numbers 20 (a) to 20 (d) based on your understanding of the following paragraph
and the related studied concepts.
A strip of metal X is immersed in the aqueous solution of salt YSO4. After some time a layer of metal Y from the salt solution is deposited on the strip of X. Whereas the metal X is used for galvanisation and metal Y is used in electrical cables.
(a) Identify the metal X. (b)What could be the metal Y? (c)Can you name the salt YSO4?
(d)Represent the above change in the form of a chemical equation.
Wednesday, February 17, 2021
Chemistry Revision test paper- 1
CLASS-XI SUBJECT- CHEMISTRY
TIME ALLOTTED: 3 hrs Max. Marks: 70
General Instructions:
1. AII the questions are compulsory. There
are 33 questions in this paper.
2. Q .1 and Q 2. Are case based
questions and have 4 parts each.
3. Q3 to Q 11. Are MCQs and carry one
mark each
4. Q 12 to Q16. Are Assertion –Reason
questions and carry one mark each.
5. Q17 to Q 25 are short answer
questions and carry two marks each.
6. Q 26 TO 30 are also short answer questions and carry three marks each
7. Q 31 to 33 are long answer questions
and carry five marks each
Q1.Case
study 1
An electron in an atom can be completely
designated with the help of four quantum numbers. Out of these, the first three
i.e; Principal (n), Azimuthal (l) and Magnetic (m) quantum numbers are obtained
from the solution of Schrodinger wave
equation while spin quantum (s) arise from the spin of the electron around its
axis whether clockwise or anti clockwise. Out of these, principal quantum
number tells about the size, Azimuthal quantum number about the shape while
Magnetic quantum number signifies the orientation of the electron orbital.
A. The
electronic configuration number of P in H3 PO4
(a)
1s2
2s2 2p6 3s2 3p3
(b) 1s2 2s2 2p6 3s2
(c)
1s2
2s2 2p6
(d) 1s2 2s2 2p6 3s2 3p6 4s1
B. How many electrons in a given atom have the following set of quantum numbers?
n = 3, l = 2, m = +2, s = -1/2
(a)
1
(b)
18
(c)
14
(d) Not possible
OR
. In an atom, the total number of electron having quantum numbers n = 4; ml =1 and ms = -1/2 is:
(a)
3
(b)
4
(c)
6
(d) 8
C. Correct set of four quantum numbers for the valence electron of rubidium ( Z = 37) is :
(a) 5, 0, 0, + 1/2
(b) 5,1,0, +1/2
(c) 5, 1, 1, +1/2
(d) 6, 0,0,+ ½
D. The electrons identified by quantum numbers n and l
(i) n =4, l = 1
(ii) n =4, l =0
(iii) n =3, l =2
(iv) n =3, l =1
can be placed in order of increasing energy from the lowest to the highest as:
(a) (iv)<(ii)<(iii)<(i)
(b) (ii)<(iv)<(i)<(iii)
(c) (i)<(iii)<(ii)<(iv)
(d) (iii)<(i)<(iv)<(ii)
Q 2. Case Study- II
The concept of hybridisation has been introduced to explain
the shapes of molecules. It involves the
intermixing of two or more atomic orbitals belonging to same atom but in different sub –shells so as to
intermix and redistribute energies to form equivalent orbitals called hybrid
orbitals. Depending upon the number and nature of the orbitals involved, the
hybridisation may be divided into sp (linear), sp2 (trigonal), sp3
( tetrahedral), sp3d3 (pentagonal bipyramidal) types. It
may be noted that the orbitals of isolated atoms never hybridise and they do so
at the time of bond formation.
(a)
If
both assertion and reason are correct and reason is correct explanation for
assertion
(b)
If
both assertion and reason are correct but reason is not correct explanation for
assertion
(c)
If
assertion is correct but reason is incorrect
(d)
If
both assertion and reason are incorrect
A. Assertion : SF6 molecule has octahedral geometry
Reason: Sulphur atom in SF6 molecule is in sp3 d hybridisation state.
B.
Assertion:
All F---S---F bonds in SF4 are greater than 900 but less than 1800
Reason: The lone pair –bond pair repulsion is weaker than bond pair – bond
pair repulsion
C.
Assertion:
If the central atom in a covalent
molecule is surrounded only by shared electron
pairs, the molecule has a regular geometry.
Reason : The force of repulsion in
all the shared electron pairs are equivalent and these are equidistant from the central atom.
OR
Assertion: There are ten valence electrons on the sulphur atom in
SF4 MOLECULE.
Reason: The structure of SF4 molecule is distorted trigonal bipyramidal.
D.
Assertion:
CIF3 has T-shape structure.
Reason: it has two lone pairs arranged at angle of 1800
Q3Whichofthefollowinghasneither secondary nor tertiary hydrogen .?
(a) Isobutane (b) Isopentane (c) Pentane (d) Neopentane
Q4. The addition of carbonyl compound to HCN is an example of
(a ) Nucleophilic substitution (b) Electrophilic addition (c) Nucleophilic
addition (d) Electrophilic substitution
Q5. In which of the following homolytic bond fission takes place (a)Alkaline hydrolysis of C2H5Cl (b) addition of HBr to double bond (c) photochlorination of methane (d) Nitration of of Benzene.
OR
The principal functional group from the following is----
(a) –CHO (b) -COOH (c) –CONH2 (d) –COCl
Q6. Pick the electrophiles from the following NH 3 ,NO2+ ,CN- ,SO3 ,ROH,FeCI3
(a) NO2+ ,SO3 , FeCI3
(b) ROH,NH3 ,CN-
(c) FeCI3 ,ROH,SO3
(d) ROH,CN- ,SO3
OR
In which of the following functional groups isomerism is not
possible
(a)Alcohols
(b) Aldehydes
( c) Alkyl halides
(d)Cyanides
Q7. The state of hybridisation of carbocation is---
(a) s p
(b) s p2
(c) sp3
(d) sp3 d
OR
What is the correct order of decreasing stability of the
following carbocations
1.CH3 ----C+ H----CH3 2. CH3---C+ H---OCH3 3. CH3---C+ H—CH2---OCH3
(a) 2>1>3
(b) 2>3>1
( c )3>1>2
(d ) 1>3>2
Q 8 . For the reaction PCI3 (g) +CI2(g)<--àP CI 5(g). The value of Kc at 2500 C is 26 mol L-1..The value of Kp at the same temperature will be
(a) 0.61 atm-1
(b) O.57 atm-1
(c) 0.83 atm-1
(d) 0.46 atm-1
Q9. The Ph of a 0.1 M Solution of acid HA is 3.The value of ionization constant Ka of this acid is
(a) 1x 10-3 (b) 1x10-5 (c) 1x10-7 (d) 3x10-1
Q10. The concentration of Hydrogen ion in a sample of soft
drink is 3.8 x10-3 M. The p H of the solution is (a) 3.84 (b)
2.42 (c)4.44 (d)
1.42
Q11 . The equilibrium constant for the reaction N2
+ O2 -à2NO at temperature T
is 4x10-4 .The value of equilibrium constant for the reaction
NO à1/2N2 +1/2 O2 at the same temperature is------ (a) 0.0025
(b) .004 (c ) 50 (d) 0.02
OR
The solubility product of Silver bromide is 7.7 x10-13
mol2 L-2. The solubility of salt will be----
(a)8.77x10-7 mol l-1 (b) 0.089 mol l-1 (c) 3.7 mol L-1 (d) 0.0077 mol L-1
Q No. 12 to 16 are
Assertion and Reason questions for which
the correct option has to be selected from the following:
(A) Both Assertion
and Reason are correct statements and Reason is correct explanation of
Assertion
(B) Both Assertion and
Reason are correct statements but Reason is not correct explanation of
Assertion
(C )Assertion is correct but Reason is not correct
(D) Assertion is not correct but Reason is correct
(E) Assertion is not correct Reason is also not correct
Q12. Assertion: One mole of NaCl contains 6.022x1023 formula units
of Sodium chloride
Reason: 58.5 g of NaCI also contains 6.022x1023 formula units of Sodium chloride
Q13. Assertion: Molarity and Molality both depend only upon
the number of moles of solute particles
Reason : Molarity of a solution does not depend upon
temperature whereas molality depends
Q14.Assertion: Many endothermic reactions that are
nonspontaneous at room temperature become spontaneous at high temperature
Reason: Entropy of the system increases with rise in
temperature
Q15. Assertion: Enthalpy of formation of HCI is equal to bond energy of HCI
Reason: Enthalpy of formation and bond energy both involve
the formation of one mole of HCI from
the elements
Q16.Assertion: Zinc displaces Copper from Copper sulphate
solution
Reason: Cu is more
reactive than Zn
OR
Assertion: Oxidation state of Hydrogen is +1 in H2 O and -1 in CaH2
Reason: CaH2
is a metal hydride
Q17. Benzyl carbocation is more
stable than ethyl carbocation. Justify
by resonating structures
Q18. Write structures
of various carbocations that can be
obtained from 2-Methyl butane. Arrange
these carbocations in increasing order of stability with reason.
OR
(a)Give bond line
formula for 2,2,4-Trimethylpentane and write IUPAC name of Iso-propyl methyl ketone.
(b)What is the hybridisation of each carbon in H2 C=C=CH2
.
Q19. Determine the degree of ionisation and p H of a 0.05 M
ammonia solution .Also calculate ionisation
constant of the conjugate acid of ammonia, given that Kb for NH3 is 1.77 x 10-5.
Q 20. 20 ml of 1.5x10-5 M BaCl2 solution is mixed
with 40ml of 0.9x10-5 M Na2SO4 solution. Will
a precipitate get formed? (solubility product for BaSO4 =1x10-10).
Q 21. Give reasons:
(a) Lakes freeze from top towards bottom
(b) Do you expect the carbon hydrides of the type (Cn H2n+2 )to act as Lewis acid or base ?Justify your answer.
Q 22. Explain electron deficient and electron rich molecular hydrides with examples.
OR
(1)
Is it correct to say that hydrogen can behave
as a metal? State the condition under
which such behaviour is possible.
(2) Temporary hard water becomes soft on heating. Explain by giving chemical equation.
Q 23. Give reasons:
(1)
Mg2+
is much more heavily hydrated than Na+. Why ?
(2) Why are halides of beryllium polymeric?
Q 24. (1) Arrange the alkaline earth metal carbonates in the decreasing order of thermal stability.
(2) LiI is more soluble than KI in ethanol. Comment on this statement.
Q 25. Explain the following
(a)
Galium has higher
ionisation enthalpy than aluminium,
(b)
Aluminium forms ( AlF6)3- ion but Boron does not form( BF6)3-
ion.
OR
(a) Explain the following
CCl4 is immiscible in water where as SiCl4 is easily hydrolysed,
(b) Select the member of group 14 that
(i) Forms the most acidic dioxide,
(II) Is commonly found in +2 oxidation state.
Q 26. 1.0 g of a mixture of carbonates of calcium and magnesium gave 240cm3 of CO2 at S.T.P. Calculate percentage composition of the mixture.
Q 27. (a) Calculate the kinetic energy of O2 molecule which has wave length of 2.5 pm.
(b) With what velocity must an electron travel so that its momentum is equal to that of a photon of wave length = 5200A0. ?
Q 28. (a) Compare the relative stabilities of O22- and N22- and comment on their magnetic behaviour,
(b) H2O molecule is a triatomic molecule but its geometry is not linear, why?
Q 29. Calculate the degree of ionisation of 0.05M acetic acid if its pka value is 4.74. How is degree of dissociation affected when the solution contains ( a) 0.01M HCl (b) 0.1M HCl
OR
Calculate the degree of ionization of 0.02M acetic acid if its Ka = 1,8x10-5. What would be the degree of ionization if the solution also contains 0.01M sodium acetate.
Q 30. (a) Balance the following reaction by half equation method ,in basic medium
MnO4- (aq) + I- (aq) à MnO2 (S) + I2 (S)
(b)Is the reaction BaO2+ H2SO4 à Ba SO4 + H2 O2 is a redox reaction.
OR
(a) Balance the following reaction by half reaction method in acidic medium
Cr2O72- + Fe2 + ---à Cr3+ + Fe3+ + H2O
(b) Identify oxidising and reducing agents in the following reaction
3CuO + 2NH3 à 3Cu +N2 +2H2 O
Q31. Comment on the following observations.
(a) F2 is more reactive than CI2.
(b) The formation of F-1 (g) from F (g) is exothermic whereas that of O2- (g) from O (g) is endothermic. Explain.
(c) Alkali metals do not form positive ions, why?
(d) Third period has eight and not eighteen elements.
(e) Second ionization enthalpy is always higher than first ionization enthalpy.
OR
Answer the following questions.
(1) Which two elements in the periodic table would you expect to combine in the most violent fashion.
(a) Cs and F (b) Cl and F
(2) Write IUPAC name for the element with atomic number 121.
(3) Which of the following has maximum number of unpaired electrons
(a) Mg2+ (b) Ti3+ (c) V3+ (d) Fe2+
(4) Write general electronic configuration of d- block elements,
(5) Mg2+ ion is smaller than O2- ion although both have same electronic configuration
Q32 (a) What volume of air containing 20% of oxygen by volume is required to completely burn 1kg of sulphur (S8 ) which contain 4% material which does not burn . . Sulphur burns according to the reaction 1/8 S8 +O2 ---àSO2
(b) When 5.0L of butane are burnt in excess of oxygen at 670 C and 2 bar pressure .Calculate the volume of CO2 evolved.
(c) If the value of “A” for a gas is zero, can it be liquefied.
OR
(a). Two gases A &B having molecular mases 60 and 45 respectively are enclosed in a vessel. The mass of A is 0.50g and that of B is 0.20g. The total pressure of the mixture is 0.921 bar. Calculate the partial pressure of two gases.
(b) Aluminium reacts with sodium hydroxide to produce sodium meta aluminate and hydrogen. What volume of hydrogen at 200 C and one bar will be released when 0.15gof aluminium reacts?
(c) Out of CO2 and NH3 gases, which is expected to show more deviation from ideal gas behaviour.
Q.33. (a) Calculate the equilibrium constant for the following reaction at 298k and 1 atm pressure:
NO (g) + 1/2O2 (g) ßàNO2 (g)
Given standard enthalpy change of formation of NO (g) is = 90.4 kJ mol-1, NO2 (g) =33.8 KJ nJ1,, Standard entropy change at 298 K is -70.8JK-1.
(b)Using the data provided, calculate the multiple bond energy (KJ mol-1 ) in C2H2 ( The bond energy of C-H bond is 350 KJmol-1 )
2C(S)+ H2 (g)-àC2 H2 (g) Change in enthalpy =225KJ mol-1
2C(S)----à 2 C (g) , change in enthalpy= 1410KJ mol-1
H2 (g) --à 2H (g) , change in enthalpy = 330 mol-1
OR
(a) Calculate the free energy change on dissolving one mole of NaCl at 250C. Lattice energy = 777.8KJ mol-1 , hydration energy=-774 KJ mol-1 of NaCl , Entropy change at 250 C =0.043 KJ mol -1
(b) For the evaporation process , H2 O(l) ß-àH2 O(g), change in enthalpy=44KJ and change in entropy=118.8x10-3 KJ k-1 .Calculate the temperature at which water vapours and water are in equilibrium.
(c) For a reaction M2O (S)--à 2 M(S) + 1/2O2 (g), change in enthalpy =30 KJ and change in entropy =0.07KJK-1 at 1 atm. Calculate up to which temp.the reaction would not be spontaneous.
Answer key is coming soon
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CARBON AND ITS COMPOUNDS-Functional Group
1. Name the functional groups present in the following compounds. a) CH 3 – CO –CH 2 –CH 2 –CH 2 –CH 3 b) CH...